C Program To Convert Infix To Postfix Expression

 

C Program for Infix to Postfix Conversion. Here we covert the infix expression to postfix expression by using stack. For example a*b-c/d is the infix expression, and equivalent postfix expression is: ab*cd/. Read more about C Programming Language. /***** You can use all the programs on www.c-program-example.com* for personal and learning purposes. Easy Tutor author of Program to convert an Infix Expression into a Postfix Expression is from United States.Easy Tutor says. Hello Friends, I am Free Lance Tutor, who helped student in completing their homework. I have 4 Years of hands on experience on helping student in completing their homework. I also guide them in doing their final year projects.

Use parantheses properly to ensure correct order for evaluating the final expression. Note: This C Program To Convert a Postfix Notation into Infix Notation using Stack has been compiled with GNU GCC Compiler and developed using gEdit Editor in Linux Ubuntu Operating System. C Program For Postfix To Infix Conversion using Stack Data Structure. Therefore, for the infix to postfix conversion algorithm, we have to define the operator precedence inside the algorithm. We did this in the post covering infix, postfix and prefix expressions. Only one stack is enough to convert an infix expression to postfix expression. BackTracking Dynamic Programming Hackerrank Others Pre-processing. C program to convert infix to postfix using stack, What is mean by infix to postfix conversion and how to convert infix to postfix using stack. Infix to postfix converter, infix to postfix. Infix expression is the expression which contains the operator in between two operands. C Program for Infix to Prefix Conversion. G T Raju, Professor & Head, Dept. Of CSE, RNSIT #define SIZE 50 /* Size of Stack. C Program for Infix to Postfix Conversion; C Program for Evaluation of Postfix Expression 34*5+. C Program to convert Prefix Expression into Postfix. C++ Program For Infix to Postfix Expression Converter Problem:- An infix expression is the usual way we write expressions. In infix expression, operators are written in-between their operands.

Algorithm for Infix to Postfix Conversion : Using Stack

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Algorithm for Conversion Of An Expression From Infix to Postfix

Explanation :

Convert Infix To Postfix Calculator

  1. In this Algorithm we are reading token from Left to Right and Postfix expression is generated. [See What is Postfix ? ]
  2. So Entered Token may be –
    • Alphabet from A-Z or a-Z
    • Numerical Digit from 0-9
    • Operator
    • Opening And Closing Braces ( , )
  3. If Entered Character isAlphabet then Following Action Should be taken-
    • Print Alphabet as Output
  4. If Entered Character isDigit then Following Action Should be taken-
    • Print Digit as Output
  5. If Entered Character isOpening Bracket then Following Action Should be taken-
    • Push ‘(‘ Onto Stack
    • If any Operator Appears before ‘)’ then Push it onto Stack.
    • If Corresponding ‘)’ bracket appears then Start Removing Elements [Pop] from Stack till ‘(‘ is removed.
  6. If Entered Character isOperator then Following Action Should be taken-
    • Check Whether There is any Operator Already present in Stack or not.
    • If Stack is Empty then Push Operator Onto Stack.
    • If Present then Check Whether Priority of Incoming Operator is greater than Priority of Topmost Stack Operator.
    • If Priority of Incoming Operator is Greater then Push Incoming Operator Onto Stack.
    • Else Pop Operator From Stack again goto Step 6.

Here you will get algorithm and program for evolution of postfix expression in C.

In postfix or reverse polish notation, every operator follows all of its operands.

For example: 5 3 2 * +

Also Read: Infix to Postfix Conversion in C [Program and Algorithm]

Algorithm for Evaluation of Postfix Expression

Create an empty stack and start scanning the postfix expression from left to right.

Write A C Program To Convert Accepted Infix Expression To Its Equivalent Postfix Expression

  • If the element is an operand, push it into the stack.
  • If the element is an operator O, pop twice and get A and B respectively. Calculate BOA and push it back to the stack.
  • When the expression is ended, the value in the stack is the final answer.

Evaluation of a postfix expression using a stack is explained in below example:

Program for Evaluation of Postfix Expression in C

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//Assumption -- primary operators '-,+,*,/,%' operand -- a single digit
#include<stdio.h>
#define MAX 20
typedefstructstack
intdata[MAX];
}stack;
voidinit(stack*);
intfull(stack*);
voidpush(stack*,int);
{
charx;
init(&s);
printf('Enter the expression(eg: 59+3*)nSingle digit operand and operators only:');
while((x=getchar())!='n')
if(isdigit(x))
push(&s,x-48);//x-48 for removing the effect of ASCII
{
op1=pop(&s);
push(&s,val);
}
val=pop(&s);
}
intevaluate(charx,intop1,intop2)
if(x'+')
if(x'-')
if(x'*')
if(x'/')
if(x'%')
}
voidinit(stack*s)
s->top=-1;
{
return(1);
return(0);
{
return(1);
return(0);
{
s->data[s->top]=x;
{
x=s->data[s->top];
}

Output

Enter the expression(eg: 59+3*)
Single digit operand and operators only:74+5-

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Value of expression=6

Image Credit:http://cis.stvincent.edu/html/tutorials/swd/stacks/stacks.html

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